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-x^2+390x-14000=0
We add all the numbers together, and all the variables
-1x^2+390x-14000=0
a = -1; b = 390; c = -14000;
Δ = b2-4ac
Δ = 3902-4·(-1)·(-14000)
Δ = 96100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{96100}=310$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(390)-310}{2*-1}=\frac{-700}{-2} =+350 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(390)+310}{2*-1}=\frac{-80}{-2} =+40 $
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